[Build 1.2.0] feat: 更新职位规则和晋升逻辑以支持新数据结构

- 修改职位规则读取逻辑，调整列索引以适应新的数据格式
- 增加晋升级别和档次的计算逻辑，确保正确处理职务晋升
- 优化异常处理，确保在职务不存在时记录警告信息
- 更新文档以反映晋升级别档次变化的记录方式

main.py

@@ -35,7 +35,7 @@ for index, row in Promote.iterrows():
 logging.info("人员信息加载完成")
 
 Rule_Role = []
-col = 2
+col = 4
 while True: # 职位规则
     try:
         rule = pd.read_excel("原数据.xlsx", sheet_name="职位规则",usecols=f"{get_column_letter(col)}:{get_column_letter(col+1)}", header=None)
@@ -76,11 +76,13 @@ while True: # 名称变化
 
 # 读取职位对应的级别限制
 Level_Limit_tmp = pd.read_excel("原数据.xlsx", sheet_name="职位规则", usecols="A:A", skiprows=2, names=["limit"])
+Promote_Level_tmp = pd.read_excel("原数据.xlsx", sheet_name="职位规则", usecols="A:B", skiprows=2, names=["级别","档次"])
 Level_Limit = {}
+Promote_Level = {}
 for rule in Rule_Role:
     for index, row in rule["rule"].iterrows():
         Level_Limit[row["role"]] = Level_Limit_tmp.iloc[index]["limit"]
-
+        Promote_Level[row["role"]] = (Promote_Level_tmp.iloc[index]["级别"], Promote_Level_tmp.iloc[index]["档次"])
 
 logging.info("规则加载完成")
 
@@ -95,7 +97,7 @@ def split_level(level:str):
         parts = level.split('-')
         return (int(parts[0]), int(parts[1]))
     except:
-        logging.warning(f"职级[{level}]格式错误")
+        raise Exception(f"职级[{level}]格式错误")
         return (0, 0)
 
 def role_salary(role:str, time):
@@ -253,7 +255,7 @@ for index, row in BaseData.iterrows():
         History_pd = History_pd.sort_values(by="时间").reset_index(drop=True)
 
         if History_pd.at[0,"时间"] != row["入职时间"]:
-            raise Exception(f"入职时间晚于其他计算的时间:{row['入职时间']} < {History_pd.at[0,'时间']} ({History_pd.at[0,'变动原因']})")
+            raise Exception(f"入职时间晚于其他时间:{row['入职时间']} < {History_pd.at[0,'时间']} ({History_pd.at[0,'变动原因']})")
         for index, hrow in History_pd.iterrows(): # 数据计算
             # 调整职务职级
             if index > 0 and hrow["职务"] == "":
@@ -271,12 +273,26 @@ for index, row in BaseData.iterrows():
                 elif hrow["变动原因"] == "工资调标":
                     History_pd.at[index, "级别档次"] = f"{jb}-{dc}"
                 elif hrow["变动原因"] == "晋升":
-                    if role_limit(History_pd.iloc[index]["职务"]) == 99: # 99tag
-                        History_pd.at[index, "级别档次"] = f"{jb}-{dc}"
-                    elif jb == role_limit(History_pd.iloc[index]["职务"]):
-                        History_pd.at[index, "级别档次"] = f"{jb}-{dc+1}"
+                    role = History_pd.iloc[index]["职务"]
+                    if role in Promote_Level.keys():
+                        new_jb = jb + Promote_Level[role][0]
+                        new_dc = dc + Promote_Level[role][1]
+                        if pd.isna(new_jb) or pd.isna(new_dc):
+                            print(Promote_Level[role][1])
+                            raise Exception(f"级别档次计算出现NaN值：[{new_jb}]-[{new_dc}]({role})")
                         else:
-                        History_pd.at[index, "级别档次"] = f"{jb-1}-{dc-1}"
+                            new_jb = int(new_jb)
+                            new_dc = int(new_dc)
+                        if role_limit(role) == 99: # 99tag
+                            History_pd.at[index, "级别档次"] = f"{jb}-{dc}"
+                        elif new_jb < role_limit(role):
+                            History_pd.at[index, "级别档次"] = f"{jb}-{dc+1}"
+                        elif new_jb < 1 or new_dc < 1:
+                            raise Exception(f"级别档次小于0：[{new_jb}]-[{new_dc}]")
+                        else:
+                            History_pd.at[index, "级别档次"] = f"{new_jb}-{new_dc}"
+                    else:
+                        logging.warning(f"职位[{role}]不存在职级上限规则")
             # 计算工资
             History_pd.at[index, "职务工资"] = role_salary(History_pd.iloc[index]["职务"], hrow["时间"])
             History_pd.at[index, "级别工资"] = level_salary(History_pd.iloc[index]["级别档次"], hrow["时间"])

使用说明.md

@@ -35,6 +35,8 @@
 
 晋级晋档起始时间不会进行添加级别档次变化记录。
 
+晋升的级别档次变化记录：正数增加，负数减小。
+
 ## 3. 打包成 .exe 文件
 
 本程序使用Win7兼容的**Python 3.8.10**，需要在电脑上使用此版本，并确保打包的环境是此版本。